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8X^2+24X+8X^2-16X-486=0
We add all the numbers together, and all the variables
16X^2+8X-486=0
a = 16; b = 8; c = -486;
Δ = b2-4ac
Δ = 82-4·16·(-486)
Δ = 31168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31168}=\sqrt{64*487}=\sqrt{64}*\sqrt{487}=8\sqrt{487}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{487}}{2*16}=\frac{-8-8\sqrt{487}}{32} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{487}}{2*16}=\frac{-8+8\sqrt{487}}{32} $
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